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[729 fx]

I read from somewhere on the following quiz :

What is common between all these great blades?

Butterfly - Amultart, Jun Mizutani, Photino, Timo Boll Spirit
Donic - Kitex, Persson Carbotec
Joola - Chen Weixing, Fever, Rosskopf Force, Wing Fast, Wing Medium
Nittaku - Violin
Xiom - Control, Ignito, Stradivarius

[ejunkie]

The following is not tt related but it's in a book that I read. It ask the reader to solve the following in 20 minute if possible. I did every one except the last one. So I went beyond the 20 min. Let me share the problems:

These are sequence of number. The first 6 is given and the book ask for the next number.
1. 1,3,5,7,9,11,?
2. 1,3,9,27,81,243,?
3. 1,4,9,16,25,36,?
4. 1,5,12,22,35,51,?
5. 1,8,27,64,125,216,?
6. 1,6,15,28,45,66,?
7. 1,1,2,3,5,8,?
8. 2,6,12,20,30,42,?
9. 2,3,5,7,11,13,?
10. 12/7,2,2.4,3,4,6,?

[ejunkie]

Cover this up if you don't want to see the answers yet.

1. 13
2. 729
3. 49
4. 70
5. 343
6. 91
7. 13
8. 56
9. 17
10. 12

[ejunkie]

Quiz5. (I hope I got the number correct because I sm too lazy to look back to find out how many I posted):

A new Chinese table tennis equipment is just established and is selling a new candy that shape as a racket as it's first product, a gimmick of course. These candies come in ten per box, and each candy has a special packaging. During the promotion period, every three packaging can be used to exchange for another piece of the candy.
Supposed Varghese bought one box of this candy, do you know how many can he eat altogether?

[729 fx]

My guess is 11. 10 packages for 1 additional, therefore the total is 11.

[ejunkie]

729, here is a hint. Please note that every three candy wrappers (packaging) will get you one candy when you turn in the wrappers (packaging).

[729 fx]

I revised my guess to 14.
Reason being 10 candies per box entitle varghese to 3 free candies. These 3 in turn can be exchange for another one more candy. Therefore 10 + 3 + 1 = 14.

[ejunkie]

I am posting the solution to quiz5 so please don't look if you haven't figure it out and want to do it later.
quiz 5 solution:
For those who know the formula :
S=a/(1-r) = 10/ (1-1/3) = 15 candies.

or
1. after eating one box 10 candies eaten 10 wrappers
2. use 9 wrappers to get 3 candies 3 more eaten 4 wrappers left
3. use 3 wrappers to get one candy 1 candy eaten 2 wrappers left
4. borrow 1 wrapper from ejunkie, and use the three wrappers to get 1 candy
1 candy eaten 1 wrapper left
5. return the borrowed wrapper to ejunkie 0 candy eaten 0 wrapper
total number of candies eaten by Varghese 15 candies


Thank you for playing

[729 fx]

Ha Ha Ha.

That was a good and fun quiz, ejunkie.

[ejunkie]

Yes I picked this problem because it's fun. Another way of doing the problem is
1. eat all 10 candies, has 10 wrappers, and borrow 5 additional wrappers from ejunkie
2. use the 15 wrappers to get 5 candies, eat all 5 candies, and return the 5 wrappers to ejunkie.
total candies eaten is still 15. QED.